kW is the power that does real work; kVA is the total power the system must supply; power factor connects the two. Here is how they differ and how to use both when sizing equipment.

Figure 1. kVA vs kW
| Parameter | kW | kVA |
| Full name | Kilowatt | Kilovolt-ampere |
| Type of power | Real/active power | Apparent power |
| Represents | Power actually converted into useful work | Total apparent power supplied to the load |
| Depends on power factor | Yes, in AC systems | No, in its basic voltage-current calculation |
| Common applications | Power consumption and useful output | Generator, transformer, and UPS capacity |
| Relationship | kW = kVA × PF | kVA = kW/PF |
The difference between kW and kVA is mainly determined by the power factor of an AC load. While kW represents the real power used by the load, kVA reflects the apparent power required by the electrical system. Understanding power factor makes the relationship between these two values easier to see.
kW, or kilowatt, is a unit of real power, also called active power. It represents the power actually converted into useful work or other forms of energy, such as mechanical motion, heat, or light. For example, the electrical power used by a motor to produce mechanical output or by a heater to generate heat is measured in kW.
In an AC circuit, real power depends on RMS voltage, RMS current, and power factor. For a single-phase system:
kW = V × I × PF / 1,000
For a balanced three-phase system, VLL represents the RMS line-to-line voltage, and IL represents the RMS line current:
kW = √3 × VLL × IL × PF / 1,000
where:
V = RSM voltage
I = RMS current
VLL = RMS line-to-line voltage
IL= RMS line current
PF = power factor
These formulas apply to the corresponding single-phase and balanced three-phase AC systems.
kVA, or kilovolt-ampere, is a unit of apparent power. It is calculated from the RMS voltage and current without directly applying the power factor.
For a single-phase AC system:
kVA = V × I / 1,000
For a balanced three-phase system:
kVA = √3 × VLL × IL / 1,000
Apparent power represents the combined effect of real and reactive power in an AC system. It indicates the total voltage-and-current loading that equipment such as transformers, generators, and switchgear must handle.
Unlike real power, apparent power does not indicate how much energy is converted into useful work. The relationship between apparent power and real power is determined by the power factor.
Reactive power, measured in VAR or kVAR, is associated with the periodic storage and return of energy in inductive and capacitive components. Motors and transformers, for example, require reactive power to establish magnetic fields.
Reactive power represents energy exchanged between the source and reactive components. It produces no net energy transfer over an ideal AC cycle, but the associated current still flows through and loads conductors, transformers, generators, and switchgear.
Power factor (PF) describes the relationship between real power and apparent power in an AC system.
It can be expressed as:
PF = kW / kVA
(this is the true power factor, the ratio of real power to apparent power)
Rearranging the formula gives:
kW = kVA × PF
and:
kVA = kW / PF

Figure 2. Power Triangle Diagram
A power factor of 1 means that real power and apparent power are equal. As the power factor decreases, more apparent power is required to deliver the same amount of real power.
For example, suppose a system needs to supply 80 kW of real power.
At PF = 1.0: kVA = 80 / 1.0 = 80 kVA
At PF = 0.8: kVA = 80 / 0.8 = 100 kVA
At PF = 0.7: kVA = 80 / 0.7 ≈ 114.3 kVA
The real power requirement remains 80 kW, but the apparent power requirement increases as the power factor falls.
Inductive loads such as motors can have a lagging power factor because current lags behind voltage. When voltage and current are sinusoidal, this phase angle φ gives the displacement power factor, cosφ, and it equals the true power factor. Figure 2 shows how kW, kVAR and kVA relate under those conditions.
Nonlinear loads such as switch-mode power supplies and variable-speed drives draw distorted current, and the harmonic currents can make the true power factor lower than the displacement power factor. So for these loads, cosφ alone can overstate the real figure. For practical measurements and equipment sizing, use the true power factor, calculated as real power divided by apparent power.
This is one reason kVA matters when determining the capacity of electrical equipment. A system may require a certain amount of real power while placing a larger apparent-power demand on the electrical infrastructure.
The conversion between kVA and kW is straightforward when the power factor is known.
Use:
kW = kVA × PF
For example, if a generator is supplying 50 kVA at a power factor of 0.8:
kW = 50 × 0.8 = 40 kW
So the corresponding real power is 40 kW.
Use:
kVA = kW / PF
For example, a load requires 60 kW at a power factor of 0.75:
kVA = 60 / 0.75 = 80 kVA
The electrical system therefore needs to handle 80 kVA of apparent power to supply the 60 kW real-power load at that power factor.
A kW-to-kVA conversion cannot be determined accurately without knowing the power factor.
For example, a 100 kW load could correspond to:
100 kVA at PF = 1.0
125 kVA at PF = 0.8
Therefore, simply treating kW and kVA as interchangeable can lead to incorrect equipment sizing.
For equipment selection, the power factor should come from the equipment nameplate, manufacturer documentation, measured operating data, or an appropriate power-quality measurement rather than being assumed without justification.
| Apparent power | PF=1.0 | PF=0.9 | PF=0.8 | PF=0.7 |
| 1 kVA | 1.0kW | 0.9 kW | 0.8 kW | 0.7 kW |
| 10 kVA | 10 kW | 9 kW | 8 kW | 7 kW |
| 100 kVA | 100 kW | 90 kW | 80 kW | 70 kW |
All values are calculated as kW = kVA × PF, using the power factor listed in each column. If the power factor is unknown, no universal default value can give an accurate conversion. Take the PF from the equipment datasheet or measure it on the load.
Whether kVA or kW is more relevant depends on the equipment and load conditions being evaluated. For generators, transformers, UPS systems, and other power equipment, sizing should consider more than the steady-state kW load. The following checks can help determine the required capacity.
6.1 Check Continuous kW
Start by determining the continuous real power requirement of the load. Add the kW demand of the equipment expected to operate at the same time under normal conditions.
For motors, check what the kW value represents. A motor's rated kW on the nameplate typically refers to its mechanical shaft output power, not its electrical input power. Because of motor losses, electrical input power is higher than rated mechanical output. Estimate input kW as:
Input kW = Output kW / Efficiency
The resulting input kW can then be used when evaluating the electrical load.
6.2 Check Continuous kVA
Next, determine the continuous apparent power required by the load. When kW and operating power factor are known:
kVA = kW / PF
The selected equipment should have sufficient continuous kVA capacity for the expected operating load.
This check is particularly important for transformers and generators, which are commonly rated in kVA. For UPS systems, both the kVA and kW ratings must be considered.
6.3 Check Motor Starting kVA
Steady-state load calculations may not capture the requirements of motor starting. A motor can draw substantially higher current during startup than during normal operation, temporarily increasing its apparent-power demand.
Check the motor's starting current or starting kVA and determine whether the generator, transformer, UPS, or other upstream equipment can handle the starting condition without exceeding its limits or causing unacceptable voltage drop.
6.4 Check Allowable Voltage Drop
High current, especially during motor starting, can cause voltage drop in the power system. Check the voltage at the load under both normal operating and starting conditions where applicable.
The allowable voltage drop depends on the application, system design, applicable requirements, and equipment specifications. Use the actual system conditions and relevant requirements rather than applying a single generic value.
6.5 Check Load Power Factor
Confirm the expected operating power factor of the load. For a given real-power demand, a lower power factor results in higher apparent power and current.
kVA = kW / PF
This is important when sizing generators, transformers, UPS systems, and other equipment whose capacity is affected by voltage and current.
6.6 Check Three-Phase Load Balance
For a three-phase system, check how the loads are distributed across the three phases. Significant phase imbalance can cause uneven phase currents and affect system performance and equipment loading.
Where applicable, distribute single-phase loads as evenly as practical and follow the equipment manufacturer's requirements for phase balance.
6.7 Check Nonlinear Load Characteristics
Identify nonlinear loads such as switch-mode power supplies, variable-frequency drives, and other power-electronic equipment. These loads can produce harmonic currents that affect power quality, equipment heating, and system loading.
For systems with significant nonlinear loads, check the applicable harmonic requirements and the manufacturer's specifications to ensure that the selected equipment is suitable for the expected load characteristics.
6.8 Check Environmental Derating Conditions
The available capacity of electrical equipment may be reduced under certain installation and environmental conditions. Check factors such as ambient temperature, altitude, ventilation, enclosure conditions, and installation method where applicable.
Use the manufacturer's derating information to determine the actual usable capacity under the intended operating conditions.
6.9 Check Manufacturer Requirements and Capacity Margin
Finally, check the manufacturer's requirements for minimum capacity, overload capability, starting loads, load characteristics, and recommended capacity margin.
Do not assume that a fixed percentage of spare capacity is appropriate for every application. The required margin depends on the equipment type, load profile, operating conditions, future expansion needs, and manufacturer guidance.
6.10 Additional Checks for UPS Systems
UPS sizing requires two separate capacity checks. The expected load must not exceed either the UPS kW rating or its kVA rating. A load may be within one rating while exceeding the other, so both limits must be verified against the specific UPS specifications.
Battery capacity should be evaluated separately from the UPS power rating. Confirm the required battery runtime at the expected load and operating conditions, then verify that the selected battery configuration can provide the required backup time.
Using these checks together provides a more complete basis for selecting generators, transformers, UPS systems, and other power equipment than comparing the load's kW value alone.
Power factor correction can reduce reactive power demand and improve the utilization of an AC power system. However, the appropriate correction method depends on the type of load, its operating conditions, and the presence of harmonics.
For suitable inductive loads, power factor correction capacitors can compensate for reactive power and improve the displacement power factor. Automatic capacitor banks can be used when the reactive power demand varies with the load.
However, capacitors do not directly eliminate harmonic distortion. In systems with significant nonlinear loads, power-electronic solutions or harmonic-filtering equipment may be more appropriate than conventional capacitor correction alone.
Before installing a capacitor bank, evaluate the system's harmonic levels and load characteristics. Nonlinear loads can produce harmonic currents, and adding capacitors to a system with significant harmonics can introduce or worsen resonance under certain conditions.
A suitable assessment should therefore include:
• Harmonic evaluation to identify the level and characteristics of harmonic currents
• Resonance risk assessment to determine whether the capacitor bank could interact with system inductance
• Switching and control design to determine how capacitor stages will be connected and disconnected as the load changes
• Load-profile analysis to determine the required compensation capacity under actual operating conditions
These checks help avoid overcompensation, unnecessary capacitor operation, and resonance-related problems.
The required correction capacity should be based on the actual reactive power demand and how the load changes over time. A fixed capacitor size may not be suitable for a facility with widely varying loads.
Automatic capacitor banks can adjust the amount of compensation by switching capacitor stages according to the system's reactive power demand. The control strategy should be designed to maintain the required power factor without excessive compensation.
Power factor correction should therefore be treated as a system-level design task rather than simply adding capacitors to a low-power-factor load. The final solution should account for the load profile, harmonic conditions, resonance risk, switching requirements, and applicable equipment specifications.
kW is the work your equipment does, and kVA is the total load your supply has to carry. Power factor sits between them. Size by converting kW to kVA with a realistic PF, then confirm the equipment covers both limits. For your own system, start by reading the nameplate, finding the PF of your main loads, and checking your utility's tariff.